35p+6p^2=-25

Solution for 35p+6p^2=-25 equation:

35p+6p^2=-25

We move all terms to the left:

35p+6p^2-(-25)=0

We add all the numbers together, and all the variables

6p^2+35p+25=0

a = 6; b = 35; c = +25;
Δ = b2-4ac
Δ = 352-4·6·25
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-25}{2*6}=\frac{-60}{12}
=-5
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+25}{2*6}=\frac{-10}{12}
=-5/6
$